Huygensova naloga
 
 x
1
=aq, x
2
=x
1
q =aq
2
, ... , x
n
=x
n−1
q =aq
n
, b =aq
n+1
.
 0<a<b q > 1 a<x
1
<x
2
<...<x
n
<b.
 a,x
1
,x
2
,...,x
n
,b 
 q =
n+1
p
b/a 
 u (aq,aq
2
,...,aq
n
) R
n
+
 1


n+1
√
a+
n+1
√
b

n+1
 
 
 ℄ 
 
 ℄ ℄ 
 ℄ ℄ 161–167

Vesti
 
 
 
 
 
 
 
 
 
 Obzornik mat. fiz. 55 (2008) 5

Ob 80. obletnici rojstva Franceta Križaniˇ ca
 
 
 
 
 
 
 
 
 
 
 
 
 
 Obzornik mat. fiz. 55 (2008) 5

Vesti

 
 
 
 
 
 
 Obzornik mat. fiz. 55 (2008) 5

Ob 80. obletnici rojstva Franceta Križaniˇ ca
 
 
 
 Obzornik mat. fiz. 55 (2008) 5